解答题2-4 取ACB整体为受力分析对象: ΣMB =0, F.a -RAy.2a =0 RAy =F/2(向上) . AC是二力杆,据图中尺寸知: AC连线与水平方向夹角45度,即 |RAx| =|RAy| 即 RAx =F/2(向右) . ΣFx =0, RAx -F +RBx =0 F/2 -F +RBx =0 RBx = F/2(向右) . Σ...4487
1 如图所示一三铰钢架,试求A.B.C处的约束反力。,,,,,夹野托迸4462