sql语句如何查询一个表中某两个字段的相同数据?

2024-10-28 11:07:40
推荐回答(5个)
回答(1):

查询一个表中某两个字段的相同数据代码是:Select Name,ID From A group by Name,ID having count (*)>1。

结构化查询语言(Structured Query Language)简称SQL,结构化查询语言是一种数据库查询和程序设计语言,用于存取数据以及查询、更新和管理关系数据库系统;

sql 语句就是对数据库进行操作的一种语言。

sql="select * from 数据表 where字段名=字段值 order by字段名[desc]"(按某个字段值降序排列,默认升序ASC);

sql="select * from 数据表 where字段名like '%字段值%' order by 字段名 [desc]";

sql="select top 10 * from 数据表 where字段名=字段值 order by 字段名 [desc]";

sql="select top 10 * from 数据表 order by 字段名 [desc]";

sql="select * from 数据表 where字段名in ('值1','值2','值3')";

sql="select * from 数据表 where字段名between 值1 and 值2"。

sql语句:

更新:update table1 set field1=value1 where 范围;

查找:select * from table1 where field1 like '%value1%' (所有包含'value1'这个模式的字符串);

排序:select * from table1 order by field1,field2 [desc];

求和:select sum(field1) as sumvalue from table1;

平均:select avg(field1) as avgvalue from table1;

最大:select max(field1) as maxvalue from table1;

最小:select min(field1) as minvalue from table1[separator]。

回答(2):

除重
select distinct A.ID AS AID,A.Name AS AName,B.ID AS BID,B.Name AS BName from A inner join B on(A.Name=B.Name and A.ID=B.ID)
不除重
select A.ID AS AID,A.Name AS AName,B.ID AS BID,B.Name AS BName from A inner join B on(A.Name=B.Name and A.ID=B.ID)

回答(3):

select * from A
inner join B on A.Name = B.Name and A.ID = B.ID
where A.Name = '张三' and A.ID = '008'
内连接即可

回答(4):

Select Name,ID From A group by Name,ID having count (*)>1

回答(5):

select name,id,count(*) from a group by name,id