1-(cosx)^1⼀2的等价无穷小和1-cosx的有关系么?还有1-cos(x)^1⼀2的等价无穷小是

2024-11-16 00:16:31
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回答(1):

cosx-1和-(x^2)/2是等价无穷小,即1-cosx和(x^2)/2为等阶无穷小
还得说明x→0,否则x→∞,1-cosx与x^2/2就不能是等阶无穷小.
应该是当x→0,1-cosx~x^2/2,
其实这个的严格证明还得用泰勒公式,用泰勒公式将cosx在x0=0处展开得:
cosx=1-x^2/2+x^4/4-x^6/6+...+(-1)^nx^2n/2n...
从而1-cosx=x^2/2-x^4/4+x^6/6+...+(-1)^nx^2n/2n...
故x^2/2是1-cosx的主部,
所以lim[(1-cosx)/(x^2/2)]=1(x→0),由等价无穷小量的定义可知1-cosx与x^2/2为等价无穷小量,即cosx-1和-(x^2)/2是等价无穷小量.