C++括号匹配程序老有错,求大神帮忙

2025-03-21 20:52:56
推荐回答(1个)
回答(1):

你写的这个类比较乱,里面的问题也不少。

(1)你声明的str数组根本就没有使用,那声明这个有什么意义。

(2)既然用的是elem数组,那为什么是int类型的,对于括号怎么存放??

(3)elem数组在声明的时候,并没有使用类中定义的elem变量,而是在initlist函数中,定义了一个同名的局部变量,这个变量在出了函数之后就没有意义了。后面根本就没有办法使用。


建议修改的地方:

(1)把str的声明和初始化都去掉,反正没有使用。

(2)用elem数组存放输入的字符串,并将类型改为char*类型。

所以修改的部分为:

class arrstack
{
    private:
    char * str;              //存放栈元素的数组
    int maxsize;             //栈中最多可存放的元素个数
    int top;                 //栈顶位置,应小于maxsize
    public:
    int match(arrstack &L);         //判别表达式中的括号是否配对
    arrstack()               //构造函数,固定长度的栈
    {
        int maxsize = 100;
        top = -1;
    }
    ~arrstack()                   //析构函数
    {
        delete[] elem;
    }
    char * elem;
    int length;
    int listsize;
    //void displist(arrstack &L);            //输出顺序表
    void initlist(arrstack &L);            //初始化顺序表
    void creat(arrstack &L);               //创建顺序表
};
void arrstack::initlist(arrstack &L)         //初始化顺序表
{
    int listsize = 100;
    elem = new char[listsize];
    int length = 0;                 //顺序表中元素个数
}

最后的结果为:

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