00cr17ni14mo2是什么材质00cr17ni14mo2成分,密度多少

2025-01-14 05:05:37
推荐回答(3个)
回答(1):

00Cr17Ni14Mo2N尿素级不锈钢
化学成分:
C碳:≤0.030
Cr铬:17.0~18.5
Ni镍:13.0~15.0
锰Mn:≤2.0
Mo钼:2.0~3.0
Si硅:≤1.0
S硫:≤0.22
P磷:≤0.045
N氮:0.19
机械性能抗拉强度:σb≥520Mpa
延伸率:δ≥45%
材料说明在316L的基础上,为尿素生产而开发的不锈钢,对Cr、Ni、Mo的最低含量做了另外的限制;目的是使不锈钢在最终热处理后得到全奥氏体组织,并使铁素体含量不超过0.6%,同时对晶间腐蚀倾向试验和选择性腐蚀提出了要求
典型工况尿素高压设备衬里、内件及相应的管道
应用领域尿素生产
配套焊材AVESTA 316L-Si、AWS A5.9 ER316LSi
供货形态板材、棒材、法兰、焊材

回答(2):

00Cr17Ni14Mo2是在316不锈钢基础上降低碳含量,属超低碳钢,对各种有机酸、无机酸、碱类、盐类均有良好的耐蚀性能,具有良好的耐敏化态晶间腐蚀的性能。焊接性能良好,适合多层焊接,焊后不需要热处理,焊后无刀口腐蚀倾向。
00Cr17Ni14Mo2化学成分:

碳C 硅Si 锰Mn 磷P 硫 S 铬Cr
≤0.030 ≤1.00 ≤2.00 ≤0.045 ≤ 0.030 16.00~18.00
镍Ni 钼Mo 氮N 铜Cu 铁Fe 铌Nb
10.00~14.00 2.00~3.00 ~ ~ ~ ~
硼B 钛Ti: 铝Al 钒 V 钨W 铈Ce
~ ~ ~ ~ ~ ~
密度是7.93!!!

回答(3):

00Cr17Ni14Mo2超低碳奥氏体不锈钢,焊接性能良好,适合多层焊,焊后无刀口腐蚀倾向,对亚硫酸、硫酸、磷酸、醋酸、甲酸、氯盐、卤素、亚硫酸盐均有良好的耐蚀性。一般用于制造化工、化肥和化纤等工业设备,如容器、管道及结构件。
化学成份:
碳 C :≤0.030
硅 Si:≤1.0[1]
锰 Mn:≤2.00
硫 S :≤0.030
磷 P :≤0.045
铬 Cr:16.00~18.00
镍 Ni:12.00~15.00
钼 Mo:2.00~3.00
氮 N :≤0.10
力学性能:
抗拉强度 σb (MPa):≥480
条件屈服强度 σ0.2 (MPa):≥177
伸长率 δ5 (%):≥40
断面收缩率 ψ (%):≥60
硬度 :≤187HB;≤90HRB;≤200HV

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