我们公司组织篮球比赛,共6个参赛队,请问要怎么安排赛程

2025-03-11 08:17:11
推荐回答(5个)
回答(1):

完全按你的要求是没有办法安排好的
基本接近到时可以

第一种
1、抽签分3组 淘汰赛(3场)
A对B
C对D
E对F
2、胜方3队进行循环赛(3场)
胜积2分 负积1分 弃权0分
积分相同 按两队比赛那场的胜负定 可决出123名

第二种
1、抽签分2组 循环赛(6场)
ABC一组 DEF一组
胜积2分 负积1分 弃权0分
积分相同 按两队比赛那场的胜负定
2、胜方2队 进行决赛 争冠亚军
如果一定要季军 可多在决赛前多举行一场34名的比赛 由循环赛排第二的球队举行

回答(2):

让六支队随意抽签(两个1,两个2,两个3),抽到相同的号码比赛,会有3支队伍胜出(其余三队淘汰),胜出的3支队打循环赛,赢2场的第一,赢一场的第二,其次为第三,还可再打一场(第一第二),打出冠亚军!

回答(3):

分两个组:
ABC,三队捉对厮杀,决出第一名(三场即:AB,AC,BC)
EDF,三队捉对厮杀,决出第一名。(三场即:ED,EF,DF)
两个小组第一名决出冠军、亚军。(壹场)
至于季军,可以计小分决出(例如使用净胜球)。成绩最好的作为第三名!

回答(4):

两两淘汰。1)AB 2)CD 3)EF 。胜者进入4强,剩下一个由输得最少的一个补上,算小分。
四强两两淘汰。4,5 。已经比过的队不相遇(即,输的那一队不与赢他的那一队比)。胜者进入决赛,负者争季军。

其实六场比赛更好,分为1——2——1——1——1。即两两淘汰后赢的三队打循环赛。最后的循环赛看谁赢得多(都是是一胜一负时算小分)。

回答(5):

最快的方法是,第一轮淘汰赛,第二轮小组赛,算下来好像是需要6场球

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