灯泡电阻R= U2 P = (12V)2 6W =24Ω；灯泡在铅档册9V的电压下消槐宏耗的功蠢键率P实= U实2 R = (9V)2 24Ω =3.375W；电路电流I= U R = 12V 24Ω =0.5A；串联电阻两端的电压U串=36V-12V=24V；串联的电阻为R串= U串 I = 24V 0.5A =48Ω；故答案为：3.375；48．
