如何获取classpath下的log4j.properties文件的绝对路径

2024-11-18 10:31:25
推荐回答(1个)
回答(1):

java获得当前文件路径

第一种:
File f = new File(this.getClass().getResource("/").getPath());
System.out.println(f);
结果:
C:\Documents%20and%20Settings\Administrator\workspace\projectName\bin
获取当前类的所在工程路径;
如果不加“/”
File f = new File(this.getClass().getResource("").getPath());
System.out.println(f);
结果:
C:\Documents%20and%20Settings\Administrator\workspace\projectName\bin\com\test
获取当前类的绝对路径;

第二种:
File directory = new File("");//参数为空
String courseFile = directory.getCanonicalPath() ;
System.out.println(courseFile);
结果:
C:\Documents and Settings\Administrator\workspace\projectName
获取当前类的所在工程路径;

第三种:
URL xmlpath = this.getClass().getClassLoader().getResource("selected.txt");
System.out.println(xmlpath);
结果:
file:/C:/Documents%20and%20Settings/Administrator/workspace/projectName/bin/selected.txt
获取当前工程src目录下selected.txt文件的路径

第四种:
System.out.println(System.getProperty("user.dir"));

结果:
C:\Documents and Settings\Administrator\workspace\projectName
获取当前工程路径

第五种:
System.out.println( System.getProperty("java.class.path"));
结果:
C:\Documents and Settings\Administrator\workspace\projectName\bin
获取当前工程路径