求学霸帮忙讲下这道题,初三的数学,二次函数,化为顶点式

2024-11-20 21:21:29
推荐回答(2个)
回答(1):

y=3(x² + 2x/3)
=3[x² + 2x/3 + (1/3)² - (1/3)²]
=3(x + 1/3)² - 3•(1/3)²
=3(x + 1/3)² - 1/3

回答(2):

y=3x^2+2x
=3*(x^2+2x/3)
=3*(x+1/3)^2-1/3