[求助]这个二重函数的积分用matlab怎么求？（关于dblquad函数的用法）

你的完全没问题啊 可以计算出结果 检查你的版本
f =
-(2*exp(15876/((3344*t1)/25 - 73568/125)) + 2*exp(63504/((3344*t1)/25 - 73568/125)) + 2*exp(142884/((3344*t1)/25 - 73568/125)) + 2*exp(254016/((3344*t1)/25 - 73568/125)) + 2*exp(396900/((3344*t1)/25 - 73568/125)) + 2*exp(571536/((3344*t1)/25 - 73568/125)) + 2*exp(777924/((3344*t1)/25 - 73568/125)) + 2*exp(1016064/((3344*t1)/25 - 73568/125)) + 2*exp(1285956/((3344*t1)/25 - 73568/125)) + 2*exp(1587600/((3344*t1)/25 - 73568/125)) + 2*exp(1920996/((3344*t1)/25 - 73568/125)) + 2*exp(2286144/((3344*t1)/25 - 73568/125)) + 2*exp(2683044/((3344*t1)/25 - 73568/125)) + 2*exp(3111696/((3344*t1)/25 - 73568/125)) + 2*exp(3572100/((3344*t1)/25 - 73568/125)) + 2*exp(4064256/((3344*t1)/25 - 73568/125)) + 2*exp(4588164/((3344*t1)/25 - 73568/125)) + 2*exp(5143824/((3344*t1)/25 - 73568/125)) + 2*exp(5731236/((3344*t1)/25 - 73568/125)) + 2*exp(6350400/((3344*t1)/25 - 73568/125)) + 2*exp(7001316/((3344*t1)/25 - 73568/125)) + 2*exp(7683984/((3344*t1)/25 - 73568/125)) + 2*exp(8398404/((3344*t1)/25 - 73568/125)) + 2*exp(9144576/((3344*t1)/25 - 73568/125)) + 2*exp(9922500/((3344*t1)/25 - 73568/125)) + 2*exp(10732176/((3344*t1)/25 - 73568/125)) + 2*exp(11573604/((3344*t1)/25 - 73568/125)) + 2*exp(12446784/((3344*t1)/25 - 73568/125)) + 2*exp(13351716/((3344*t1)/25 - 73568/125)) + 2*exp(14288400/((3344*t1)/25 - 73568/125)) + 2*exp(15256836/((3344*t1)/25 - 73568/125)) + 2*exp(16257024/((3344*t1)/25 - 73568/125)) +
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