高数题,求不定积分,求解答,谢谢!

2024-11-16 13:43:54
推荐回答(1个)
回答(1):

∫ x^2.arctanx/(1+x^2) dx
=∫ [ 1-1/(1+x^2) ].arctanx dx
=∫ arctanx dx - ∫ arctanx/(1+x^2) dx
=xarctanx -∫ x/(1+x^2) dx - ∫ arctanx darctanx
=xarctanx - (1/2)ln|1+x^2| - (1/2)(arctanx)^2 + C