高一化学 请问 常温常压下,2.8g氮气和一氧化碳的混合气体所含原子数为0.2NA。这句话为什么

2025-03-29 07:10:05
推荐回答(4个)
回答(1):

这句话是正确的,设N2的物质的量为x,CO的物质的量为y
所以28(x+y)=2.8g,那么x+y=0.1mol
所含原子物质的量为n=2x+2y=2(x+y)=0.2mol
根据阿伏伽德罗定律可知:所含原子数量为0.2NA

阿伏伽德罗定律主要说明:同温同压下,相同体积的任何气体含有相同的分子数,称为阿伏加德罗定律。气体的体积是指所含分子占据的空间,通常条件下,气体分子间的平均距离约为分子直径的10倍,因此,当气体所含分子数确定后,气体的体积主要决定于分子间的平均距离而不是分子本身的大小。

根据PV=nRT=(N/NA)RT=(m/M)RT,可以推出下列:
(1)同温同压下,V1/V2=n1/n2(气体体积比等于物质的量之比);
(2)同温同体积时,P1/P2=n1/n2=N1/N2(压强比等于物质的量之比等于分子数之比);
(3)同温同压等质量时,V1/V2=M2/M1(体积之比等于摩尔质量之比的倒数)。

回答(2):

N2摩尔分子量14*2=28,CO摩尔分子量12+16=28。混合起来也是28。有一种理解方式可能你更好理解,假如全是氮气只有微小不可计的CO,这样是M=28;或者全是CO只有一点点微小不可计N2,M=28。还有种理解就是假如1.4g氮气和1.4gCO,分别用n=m/M,总的物质的量n=n氮气+nCO,结果是一样,主要帮助你理解

回答(3):

为什麼要乘以2我问你?两种气体就乘以2?那麼你有没有想过,M=m/n是平均摩尔质量,是"平均"的谢谢,你乘以2了还叫做什麼平均.

回答(4):

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