如何用分部积分法解反正切arctanX的不定积分?

2024-11-07 19:18:16
推荐回答(1个)
回答(1):

∫arctanxdx
=xarctanx-∫xd(arctanx)
=xarctanx-∫xdx/(1+x²)
=xarctanx-1/2*∫d(x²+1)/(x²+1)

=xarctanx-1/2*ln(x²+1)+C