过氧化钠与水反应方程式怎么用双线桥表示

2024-11-03 19:55:54
推荐回答(5个)
回答(1):

因为过氧化钠既是氧化剂又是还原剂,2mol(-1价)的氧原子,失去了2mol电子,被氧化为氧气,所以上面要填失去2个电子。

同时过氧化钠又是氧化剂,2mol(-1价)的氧原子,得到了2mol电子,被还原为-2价的氧离子,所以双线桥上应是化合价升高的失去两个电子,化合价降低的得到2个电子,而不是得到四个电子。

具体如图:

过氧化钠和水的反应首先产生过氧化氢,碱性过氧化氢不稳定,会分解:

Na₂O₂ + 2 H₂O = 2 NaOH + H₂O₂

2H₂O₂ = 2 H₂O + O₂↑,反应放热

总反应化学方程式:2Na₂O₂+ 2H₂O = 4NaOH +O₂↑


扩展资料:

过氧化钠可与水、酸反应,生成氢氧化钠和过氧化氢(过氧化氢会分解成水和氧气),也能与二氧化碳反应生成碳酸钠和氧气。

在碱性环境中,过氧化钠可以把化合物中+3价的砷(As)氧化成+5价,把+3价的铬(Cr)氧化成+6价。利用这个反应可以将某些岩石矿物中的+3价铬除去。还可以在一般条件下将有机物氧化成乙醇和碳酸盐 ,也可以与硫化物和氯化物发生剧烈反应。

过氧化钠具有强氧化性,在熔融状态时遇到棉花、炭粉、铝粉等还原性物质会发生爆炸。因此存放时应注意安全,不能与易燃物接触。它易吸潮,有强腐蚀性,会引起烧伤。

参考资料来源:百度百科——过氧化钠

回答(2):

过氧化钠和水的反应首先产生过氧化氢,碱性过氧化氢不稳定,会分解

Na2O2 + 2 H2O = 2 NaOH + H2O2

2H2O2 = 2 H2O + O2↑,反应放热

总反应化学方程式:

2Na2O2+ 2H2O = 4NaOH +O2↑

过氧化钠是钠在氧气或空气中燃烧的产物之一,纯品过氧化钠为白色,但一般见到的过氧化钠呈淡黄色,原因是反应过程中生成了少量超氧化钠(高中教科书上不区分,Na2O2为淡黄色)。过氧化钠易潮解、有腐蚀性,应密封保存。过氧化钠具有强氧化性,可以用来漂白纺织类物品、麦杆、羽毛等。

回答(3):

因为过氧化钠既是氧化剂又是还原剂,2mol(-1价)的氧原子,失去了2mol电子,被氧化为氧气,所以上面要填失去2个电子,同时过氧化钠又是氧化剂,2mol(-1价)的氧原子,得到了2mol电子,被还原为-2价的氧离子,所以双线桥上应是化合价升高的失去两个电子,化合价降低的得到2个电子,而不是得到四个电子。在这个反应中,-1价的氧离子同时参与了氧化反应与还原反应,氧化还原反应的得失电子情况要在双线桥上分别写出,而不能写在一起。

回答(4):

2NA2O2+2H2O=4NAOH+O2
O- -E=O
O- +E=O2-

回答(5):

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