班级要选出三位班干部,一人只能投一票,前三名最高票者当选。此班共有49人,而有七位候选人。

请问至少获得几票才有希望当选?要过程,答对者感激不尽~~~
2025-02-27 03:31:40
推荐回答(3个)
回答(1):

  你小子是想拉票啊,还是做数学题啊。
  一个班有49人,而有7名候选人,一人只能投一票,所以这里得先减一个7再说(不管是因为自己总是会投自己还是候选人不能投票),所以剩下42人。
  这42人如果投的很分散,也就是7个人几乎要平分天下了的那种情况并不需要你担心,因为那根本不保险。
  要做最成功的事就要做最坏的打算,怎么样才是最坏的情况呢?
  不是七个人在争三个位子,也不是某人的票数高达48票,而是你得了个第四,也就是说,四个人竞争比七个人竞争危险的多,你只要再有1/4的人支持你就已经足够了,故你要是再拿10票就很稳了----比泰山还稳,不然就重选(几率很小),要是还担心,那就再加一票。(我们把候选人标为1、2、3、4、5、6、7,假如你是4): 1 2 3 4(你) 5 6 7
  候选人投的票 : 1 1 1 1 1 1 1
  剩余人投的票 : 11 11 10 10
  总票数: 49
  ------最差的情况 (如果你可以得11票的话)

  再加上你自己的那票,总共11票,注意, 再重复一遍,是加上你自己的那票总共11票。

  具体情况还要具体分析,你们班有什么不想入选的候选人吗?有的话请看下面。
  还有一种例外情况,那就是这七个人中有人不投自己而投别人的。,。此时,最坏的情况是有三个候选人把票给了另外三个候选人,也就是
  1 2 3 4(你) 5 6 7
  候选人投的票 : 2 2 2 1
  剩余人投的票 : 10 10 10 12
  总票数: 49
  此时你只要再有12票就可以啦。
  综上,你只要有另外的十二人支持就肯定能获胜。也就是说连上你的票,总共要13票,那是特别的保险啦。
  其实你可以之接用49除以4,不过这样不能符合实际情况的复杂性,所以你得先去侦查一下有没有异常的候选人----如果这不是一个数学题的话。
  你最好检验一下有没有错误。
  本人才学哟有限,错误及不足还请高人指出,对你有用固好,没有的话希望不要怪老夫多嘴哦。祝你成功。

回答(2):

49/7=7
7+1=8
答:8票

回答(3):

只要得到至少三分之一就好了,也就是16,7票

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