已知a+b=2,ab=-1⼀2,求a(a+b)(a-b)-a(a+b)^2的值

2025-04-08 23:34:23
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回答(1):

解:原式= (a+b)(a^2 - ab) + (a+b)(a^2 + ab)
= (a+b)(a^2 - ab - a^2 - ab)
= (a+b)(-2ab)
= 2×(-2)×(-1/2)
= 2