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Excel中用VBA生成随机数

2025-03-26 10:53:16

推荐回答（2个）

回答（1）：

按照你写的这个不会大于0.08的

回答（2）：

=A1+(RAND()*0.01+0.07)*(-1)^INT(RAND()*10)

在b1 生成a1 差值在0.07和0.08之间的随机数
你可以随意调整0.01 和0.07 只要他们相加等于0.08即可
vba的话把rand换成rnd

你的代码不会大于0.08的，你看看是不是别的地方代码有问题吧

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