2a(x^2+1)^2-8ax^2因式分解

完整步骤
2024-11-22 23:57:16
推荐回答(5个)
回答(1):

2a(x²+1)²-8ax²
=2a(x^4+2x²+1)-8ax²
=2ax^4+4ax²+2a-8ax²
=2ax^4-4ax²+2a
=2a*[(x²)²-2x²+1]
=2a*(x²-1)²

回答(2):

如图

回答(3):

回答(4):

2a(x^2+1)^2-8ax^2
=2a【(x^2+1)^2-4x^2】
=2a(x²+1+2x)(x²+1-2x)
=2a(x+1)²(x-1)²

回答(5):

2a(x^2+1)^2-8ax^2
=2a[ (x^2+1)^2-4x^2 ]
=2a[ x^2+1 -2x ]. [ x^2+1 +2x ]
=2a(x-1)^2. (x+1)^2