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带受控源的电路分析

2025-03-28 23:09:50

推荐回答（1个）

回答（1）：

6v单独作用时 4A置开路，u'=-i'x1=-i'，6=(1+3)i'+5u'=-i'，i'=-6A，

4A单独作用时 6v置短路，4=i" + u"/1，u"=4-i"，又u"=5u"+3i"，-16+4i"=3i"，i"=16A，

i=i'+i"=10A。

b) c) 一样方法处理。

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