问题!!!!!!!!!!

计算2a/(a-b)(b-c)+b/(b-c)(b-a)-a/(b-a)(c-b).谢谢
2025-04-15 03:18:25
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回答(1):

2a/(a-b)(b-c)+b/(b-c)(b-a)-a/(b-a)(c-b).
=2a/(a-b)(b-c)-b/(b-c)(a-b))-a/(a-b)(b-c)
=(a-b)/(a-b)(b-c)
=1/(b-c)